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#define PROBLEM "https://judge.yosupo.jp/problem/enumerate_palindromes" #include "test/template.hpp" #include "src/string/Manacher.hpp" int main() { cin.tie(0)->sync_with_stdio(0); string S; cin >> S; const ll N = sz(S); string T(N * 2 + 1, '$'); rep(i, 0, N) T[i * 2 + 1] = S[i]; auto r = manacher(T); rep(i, 1, N * 2) { if(i & 1) cout << r[i] - 1 << " \n"[i + 1 == N * 2]; else cout << r[i] - 1 << ' '; } }
#line 1 "test/string/Manacher.test.cpp" #define PROBLEM "https://judge.yosupo.jp/problem/enumerate_palindromes" #line 1 "test/template.hpp" #include <bits/stdc++.h> using namespace std; using ll = long long; const ll INF = LLONG_MAX / 4; #define rep(i, a, b) for(ll i = a; i < (b); i++) #define all(a) begin(a), end(a) #define sz(a) ssize(a) bool chmin(auto& a, auto b) { return a > b ? a = b, 1 : 0; } bool chmax(auto& a, auto b) { return a < b ? a = b, 1 : 0; } #line 1 "src/string/Manacher.hpp" // 各位置での回文半径を求める // aaabaaa -> 1214121 // 偶数長の回文を含めて直径を知るには,N+1 個の $ を挿入して 1 を引く // $a$a$a$b$a$a$a$ -> 123432181234321 auto manacher(string s) { ll n = sz(s), i = 0, j = 0; vector<ll> r(n); while(i < n) { while(i >= j && i + j < n && s[i - j] == s[i + j]) j++; r[i] = j; ll k = 1; while(i >= k && i + k < n && k + r[i - k] < j) { r[i + k] = r[i - k]; k++; } i += k, j -= k; } return r; } #line 4 "test/string/Manacher.test.cpp" int main() { cin.tie(0)->sync_with_stdio(0); string S; cin >> S; const ll N = sz(S); string T(N * 2 + 1, '$'); rep(i, 0, N) T[i * 2 + 1] = S[i]; auto r = manacher(T); rep(i, 1, N * 2) { if(i & 1) cout << r[i] - 1 << " \n"[i + 1 == N * 2]; else cout << r[i] - 1 << ' '; } }